Last official estimated population of Sanibel city (Lee County**, Florida state) was 7,056 (year 2014)[1]. This was 0.002% of total US population and 0.03% of total Florida state population. Area of Sanibel city is 33.3 mi² (=86.1 km²)[6], in this year population density was 212.20 p/mi². If population growth rate would be same as in period 2010-2014 (+2.2%/yr), Sanibel city population in 2026 would be 9,156*.
Historical population of Sanibel city for period 1980-2014:
Estimated population for 2014[1]. Click on flag to hide it.
Population • Legends • Position

[1980-1990] +4.98 %/yr
[1990-2000] +1.06 %/yr
[2000-2005] +1.45 %/yr
[2005-2010] -0.19 %/yr
[2010-2014] +2.2 %/yr
• Cape Coral city population
14.9 mi,
26°
• Fort Myers city
20.5 mi,
55°
• North Port city
42.3 mi,
352°
• Bonita Springs city
20.8 mi,
109°
• Venice city
49.8 mi,
337°
• Naples city
28.3 mi,
137°
• Punta Gorda city
28.8 mi,
9°
• Marco Island city
43.7 mi,
144°
• Fort Myers Beach town
11.8 mi,
96°
• LaBelle city
44.5 mi,
65°
*Calculated by population.us from last known population growth rate, not official data.
**Some cities are placed on more than one county. Only 1 county is shown.
[1] Cities and Towns (Incorporated Places and Minor Civil Divisions) 2014, archived from the original, retrieved 02/23/2016
[2] City and Town Intercensal Estimates (2000-2010), archived from the original, retrieved 02/23/2016
[3] Places: 1990 and 1999 Populations, With Numeric and Percent Population Change, archived from the original, retrieved 02/23/2016
[4] Population of the 100 Largest Urban Places: 1980,
[5] Population of the 100 Largest Urban Places in history,
[6] Area, latitude longitude data, retrieved 02/23/2016
[7] Through the Decades, Overview 1790-2010, PDF, large files! >100 Mb
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